PHP copy directory from source to destination
Written by Codes Tips on May 2, 2009 – 1:02 pm -To copy a directory source to a destination directory you will need to scan the source directory with all files and directory and copy to the destination. To accomplish this we should make a recursive function that will copy the files from source to target dir. If it is not a directory in the source dir we should just copy the file to target. If it is a directory in the source dir then we should create a new dir in the target directory and apply the same mechanism, so we need to recall again the same function.
Here is the code to do this:
<? function copy_directory( $source, $destination ) { if ( is_dir( $source ) ) { @mkdir( $destination ); $directory = dir( $source ); while ( FALSE !== ( $readdirectory = $directory->read() ) ) { if ( $readdirectory == '.' || $readdirectory == '..' ) { continue; } $PathDir = $source . '/' . $readdirectory; if ( is_dir( $PathDir ) ) { copy_directory( $PathDir, $destination . '/' . $readdirectory ); continue; } copy( $PathDir, $destination . '/' . $readdirectory ); } $directory->close(); }else { copy( $source, $destination ); } } ?>
Calling the function:
copy_directory('dirnameSource','dirnameDestination');
Download copy directory code
Tags: PHP, PHP/MYSQL
Posted in Codes, PHP/MYSQL |
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October 16th, 2009 at 6:21 am
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